8x^2+80x+80=0

Solution for 8x^2+80x+80=0 equation:

8x^2+80x+80=0

a = 8; b = 80; c = +80;
Δ = b2-4ac
Δ = 802-4·8·80
Δ = 3840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3840}=\sqrt{256*15}=\sqrt{256}*\sqrt{15}=16\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-16\sqrt{15}}{2*8}=\frac{-80-16\sqrt{15}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+16\sqrt{15}}{2*8}=\frac{-80+16\sqrt{15}}{16}
$